To solve the equation \( x - 3 = 57 \), we need to isolate \( x \).

1. Add 3 to both sides of the equation:
   \[
   x - 3 + 3 = 57 + 3
   \]
   Simplifying this, we get:
   \[
   x = 60
   \]

So, the solution is \( x = 60 \).

Would you like more details or have any questions? Here are some related questions to consider:

1. How would you solve \( x - 7 = 45 \)?
2. What is the solution to the equation \( x + 5 = 23 \)?
3. If \( x - 3 = y \) and \( y = 57 \), how would you find \( x \)?
4. How can you check the solution to the equation \( x - 3 = 57 \)?
5. How would the solution change if the equation were \( x - 3 = -57 \)?

**Tip:** Always perform the same operation on both sides of the equation to keep it balanced.

Learn how to solve the linear equation x - 3 = 57 with step-by-step instructions. This problem involves key algebraic concepts such as isolating variables and applying the addition property of equality. Perfect for students in Grades 6-8.

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