Let's solve the equation:

\[
3(4z - 4) = 12
\]

### Step 1: Distribute the \(3\) on the left side of the equation:
\[
3 \cdot 4z - 3 \cdot 4 = 12
\]
This simplifies to:
\[
12z - 12 = 12
\]

### Step 2: Add 12 to both sides to eliminate the constant on the left side:
\[
12z - 12 + 12 = 12 + 12
\]
\[
12z = 24
\]

### Step 3: Divide both sides by 12 to solve for \(z\):
\[
z = \frac{24}{12} = 2
\]

### Final Answer:
\[
z = 2
\]

Do you have any questions or would you like further details?

Here are 5 related questions for you to consider:
1. What happens if the equation was \(3(4z - 4) = 24\)?
2. Can you solve \(5(3x - 2) = 20\)?
3. What would the equation look like if you expanded \(5(2y + 6)\)?
4. How would you handle an equation like \(2(a + 3) - 5 = 7\)?
5. What is the next step if the variable \(z\) had a coefficient with a fraction?

**Tip:** Always perform distribution before isolating the variable for easier solving.

Learn how to solve the linear equation 3(4z - 4) = 12 by using the distributive property and simple algebraic steps. This guide is suitable for students in Grades 6-8, covering key concepts such as distributing and isolating variables.

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