Let's solve the equation \( 8(3 - z) = 4z \).

### Step 1: Distribute the 8 on the left side.
\[
8(3 - z) = 8 \times 3 - 8 \times z = 24 - 8z
\]
So, the equation becomes:
\[
24 - 8z = 4z
\]

### Step 2: Move all terms involving \( z \) to one side of the equation.
Add \( 8z \) to both sides:
\[
24 = 4z + 8z
\]
Simplifying the right-hand side:
\[
24 = 12z
\]

### Step 3: Solve for \( z \).
Divide both sides by 12:
\[
z = \frac{24}{12} = 2
\]

Thus, the solution is \( z = 2 \).

Would you like more details or further clarification?

Here are some related questions for further practice:
1. Solve \( 5(2 - x) = 3x \).
2. Solve \( 6(y + 4) = 2y - 8 \).
3. Solve \( 10(1 - a) = 4a \).
4. Solve \( 12 - 3x = 7x + 8 \).
5. Solve \( 9(b - 5) = 6b + 10 \).

**Tip:** Always simplify both sides of an equation before attempting to isolate the variable!

Learn how to solve the linear equation 8(3 - z) = 4z with a step-by-step guide. This algebra problem involves distributing, combining like terms, and solving for the variable z. Ideal for students in Grades 7-9.

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