Let's solve the equation:

Given:
\[
2(y + 6) = 18
\]

### Step 1: Distribute the 2 on the left side
\[
2 \times y + 2 \times 6 = 2y + 12
\]
So, the equation becomes:
\[
2y + 12 = 18
\]

### Step 2: Subtract 12 from both sides to isolate the term with \( y \)
\[
2y + 12 - 12 = 18 - 12
\]
\[
2y = 6
\]

### Step 3: Divide both sides by 2 to solve for \( y \)
\[
y = \frac{6}{2} = 3
\]

So, the solution is:
\[
y = 3
\]

Would you like further details or have any questions?

Here are 5 related questions you might find helpful:
1. How would you solve \(3(x + 7) = 21\)?
2. What is the solution to \(4(y - 2) = 16\)?
3. Can you solve \(5(z + 4) = 30\)?
4. How do you approach solving \(6(a - 3) = 18\)?
5. What steps are needed to solve \(7(b + 5) = 35\)?

**Tip:** When distributing a number across terms inside parentheses, ensure you multiply each term inside the parentheses by that number.

Learn how to solve the equation 2(y + 6) = 18 with a detailed step-by-step solution. This problem involves using the distributive property and basic equation solving techniques. Suitable for students in Grades 6-8.

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