To solve the equation \( 3(x + 2) = 15 \), follow these steps:

1. **Distribute** the 3 on the left side:
   \[
   3x + 6 = 15
   \]

2. **Subtract 6** from both sides to isolate the term with \( x \):
   \[
   3x = 9
   \]

3. **Divide** both sides by 3 to solve for \( x \):
   \[
   x = 3
   \]

So, the solution is \( x = 3 \).

Would you like more details on this, or do you have any questions?

Here are 5 related questions you might find interesting:
1. How would the solution change if the equation was \( 3(x + 2) = 18 \)?
2. What happens if you divide both sides by 3 before subtracting 6?
3. How can you check your solution after finding \( x \)?
4. What if the equation was \( 3(x + 2) = 0 \)?
5. How do you solve \( 3(x + 2) = 15 \) if you wanted to use a different method, like graphing?

**Tip:** Always remember to check your solution by substituting the value back into the original equation.

Explore how to solve the linear equation 3(x+2)=15 with a step-by-step solution. This problem covers essential algebraic concepts such as the distributive property and solving for x in linear equations. Suitable for students in Grades 6-8.

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