Let's solve the equation:

\[
14x + 6 = 55x + 37
\]

### Step 1: Move all terms with \(x\) to one side of the equation.

Subtract \(14x\) from both sides:

\[
6 = 55x - 14x + 37
\]
\[
6 = 41x + 37
\]

### Step 2: Move the constant term to the other side.

Subtract 37 from both sides:

\[
6 - 37 = 41x
\]
\[
-31 = 41x
\]

### Step 3: Solve for \(x\).

Divide both sides by 41:

\[
x = \frac{-31}{41}
\]

Thus, the solution is:

\[
x = -\frac{31}{41}
\]

Would you like more details, or do you have any questions?

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Here are 5 related questions for practice:
1. Solve: \(12x + 8 = 44x + 10\)
2. Solve: \(18x - 5 = 50x + 27\)
3. Solve: \(7x + 3 = 35x + 9\)
4. Solve: \(20x + 10 = 60x + 15\)
5. Solve: \(25x + 5 = 75x + 20\)

**Tip:** Always simplify equations by moving all terms involving \(x\) to one side and constants to the other side to make solving easier.

Learn how to solve the linear equation 14x + 6 = 55x + 37 with a detailed, step-by-step solution. This problem covers key algebraic concepts such as moving terms with variables to one side and constants to the other. Suitable for students in Grades 7-9.

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