The given equation is:

\[
10 = -5x + 2y
\]

To solve for either \(x\) or \(y\), we can rearrange the equation. Let's solve for \(y\) in terms of \(x\):

1. Start by isolating \(2y\):
\[
2y = 10 + 5x
\]

2. Now, divide both sides by 2 to solve for \(y\):
\[
y = \frac{10 + 5x}{2}
\]

Simplifying:
\[
y = 5 + \frac{5x}{2}
\]

This is the equation of \(y\) in terms of \(x\). If you need to solve for \(x\), let me know!

Would you like to see more details or explore further solutions?

Here are 5 related questions:
1. How would you graph this linear equation?
2. What happens if you substitute a specific value for \(x\)?
3. Can you find the intercepts of this line?
4. How do you convert this equation to slope-intercept form \(y = mx + b\)?
5. How do we solve for \(x\) instead of \(y\)?

**Tip:** When solving equations, always perform inverse operations to isolate the variable you need to solve for.

Learn how to solve the linear equation 10 = -5x + 2y. This solution explains how to isolate variables and solve for y in terms of x. Explore algebraic concepts such as rearranging equations and solving for one variable. Suitable for Grades 8-10 students.

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