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The equation for question 67 is \( 5x + 2y - 10 = 0 \). Solving for \( y \), we get:

\[
y = -\frac{5}{2}x + 5
\]

This is in the slope-intercept form \( y = mx + b \), where the slope \( m = -\frac{5}{2} \) and the y-intercept \( b = 5 \).

Would you like to plot the graph or see more details?

Here are five related questions to extend your understanding:
1. How would you graph the line using the slope-intercept form?
2. What is the significance of the slope and y-intercept in the equation?
3. How can we find the x-intercept of this line?
4. How would the graph change if the equation was \( 5x + 2y + 10 = 0 \)?
5. What is the relationship between parallel and perpendicular lines for this equation?

**Tip:** Always check the form of the equation (slope-intercept, point-slope, or standard form) to quickly determine key graphing features like slope and intercepts.

Learn how to solve the linear equation 5x + 2y - 10 = 0 and convert it into slope-intercept form. This problem involves basic algebraic concepts and the slope-intercept formula, suitable for students in Grades 9-10.

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