Math Problem Statement

solve this step by step

Solve step by step: 2 * (dy/dt) + (1/t) * y = 1 + sqrt(t) * e^t (for t > 0).

Solution

PIL import Image import pytesseract

Load the uploaded image

image_path = '/mnt/data/1736936480049rm4473n1.jpg' image = Image.open(image_path)

Use OCR to extract the mathematical content

extracted_text = pytesseract.image_to_string(image, config='--psm 6')

extracted_textThe equation extracted from the image is approximately:

2dydt+1ty=1+tet(for t>0).2 \frac{dy}{dt} + \frac{1}{t} y = 1 + \sqrt{t} e^t \quad (\text{for } t > 0).

Let us solve this step by step. This is a first-order linear differential equation.

Step 1: Write the equation in standard form

Divide the entire equation by 2 to make the coefficient of dydt\frac{dy}{dt} equal to 1: dydt+12ty=12+t2et.\frac{dy}{dt} + \frac{1}{2t} y = \frac{1}{2} + \frac{\sqrt{t}}{2} e^t.

Step 2: Find the integrating factor

The integrating factor is given by: μ(t)=e12tdt=e12lnt=t1/2.\mu(t) = e^{\int \frac{1}{2t} dt} = e^{\frac{1}{2} \ln t} = t^{1/2}.

Step 3: Multiply through by the integrating factor

Multiply the entire equation by t1/2t^{1/2}: t1/2dydt+t1/22ty=t1/2(12+t2et).t^{1/2} \frac{dy}{dt} + \frac{t^{1/2}}{2t} y = t^{1/2} \left(\frac{1}{2} + \frac{\sqrt{t}}{2} e^t \right).

This simplifies to: ddt(t1/2y)=t1/22+t2et.\frac{d}{dt} \left( t^{1/2} y \right) = \frac{t^{1/2}}{2} + \frac{t}{2} e^t.

Step 4: Integrate both sides

Integrate both sides to find yy: t1/2y=t1/22dt+t2etdt.t^{1/2} y = \int \frac{t^{1/2}}{2} dt + \int \frac{t}{2} e^t dt.

First integral:

t1/22dt=1223t3/2=13t3/2.\int \frac{t^{1/2}}{2} dt = \frac{1}{2} \cdot \frac{2}{3} t^{3/2} = \frac{1}{3} t^{3/2}.

Second integral:

For t2etdt\int \frac{t}{2} e^t dt, we use integration by parts: Let u=tu = t, dv=12etdtdv = \frac{1}{2} e^t dt, so du=dtdu = dt and v=12etv = \frac{1}{2} e^t.

Then: t2etdt=12tet12etdt=12tet12et=12et(t1).\int \frac{t}{2} e^t dt = \frac{1}{2} t e^t - \int \frac{1}{2} e^t dt = \frac{1}{2} t e^t - \frac{1}{2} e^t = \frac{1}{2} e^t (t - 1).

Step 5: Combine the results

Now, substitute back into the equation for t1/2yt^{1/2} y: t1/2y=13t3/2+12et(t1)+C,t^{1/2} y = \frac{1}{3} t^{3/2} + \frac{1}{2} e^t (t - 1) + C, where CC is the constant of integration.

Step 6: Solve for yy

Divide through by t1/2t^{1/2} to isolate yy: y=13t+12t1/2et(t1)+Ct1/2.y = \frac{1}{3} t + \frac{1}{2} t^{1/2} e^t (t - 1) + \frac{C}{t^{1/2}}.

This is the solution.

Would you like more details about any step?

Related Questions

  1. What are some other methods to solve linear differential equations?
  2. How do you handle cases where t=0t = 0 in the context of the integrating factor?
  3. What is the role of the integrating factor in simplifying these equations?
  4. How does integration by parts work in a general sense?
  5. Can this method be extended to second-order differential equations?

Tip

Always check the form of the differential equation before proceeding—deciding if it is linear, separable, or exact can simplify the solution process.

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Math Problem Analysis

Mathematical Concepts

Differential Equations
Integrating Factor Method
Integration Techniques

Formulas

Linear first-order differential equation: dy/dt + P(t)y = Q(t)
Integrating Factor: μ(t) = e^∫P(t)dt
Integration by parts: ∫u dv = uv - ∫v du

Theorems

Method of Integrating Factor

Suitable Grade Level

Grades 11-12