https://file.aiquickdraw.com/mathbot/file/1725895135784ixsc0j8p.jpg

Let's go through the math problems one by one based on the image you uploaded. Here's a breakdown:

---

**Problem Description:**
Mariel has a cellphone plan with a monthly fee of ₱2,500, which includes 240 minutes of call time. For any additional minute of usage beyond 240 minutes, she is charged ₱7.50 per minute.

---

### **Question 6:** 
**Which of the following pertains to the monthly cost function?**

Given:
- ₱2,500 base fee.
- Charges ₱7.50 per minute for calls exceeding 240 minutes.

Let \( x \) represent the number of minutes exceeding 240 minutes.

The correct cost function should reflect this:
- If Mariel does not exceed 240 minutes, the cost is ₱2,500.
- If she exceeds 240 minutes by \( x \), her additional cost is \( 7.50x \).

Thus, the correct cost function should be:
\[ C(x) = 2,500 + 7.50x \]
(The choice will depend on the provided options, but this matches the structure.)

---

### **Question 7:**
**What value of \( x \) will not require any additional charge in her monthly bill?**

No additional charges occur when Mariel does not exceed 240 minutes. Therefore, \( x = 0 \), which means that:
\[ x \leq 240 \text{ minutes} \]

---

### **Question 8:**
**How many additional minutes of call did she make if she paid ₱2,800?**

Given that the base cost is ₱2,500, and each additional minute costs ₱7.50:

The additional cost:
\[ 2,800 - 2,500 = 300 \text{ pesos} \]

To find the number of extra minutes:
\[
\frac{300}{7.50} = 40 \text{ minutes}
\]
So, she made an additional 40 minutes of call.

---

### **Question 9:**
**How much is her monthly cost if she made an additional usage of 20 minutes of call?**

Additional usage of 20 minutes would cost:
\[
20 \times 7.50 = 150 \text{ pesos}
\]
Thus, her total monthly cost would be:
\[
2,500 + 150 = 2,650 \text{ pesos}
\]

---

### **Question 10:**
**How much will she need to pay from using a total of 350 minutes of call in one month?**

If she used 350 minutes, the number of extra minutes beyond the 240-minute limit is:
\[
350 - 240 = 110 \text{ minutes}
\]
The additional cost for 110 minutes is:
\[
110 \times 7.50 = 825 \text{ pesos}
\]
Therefore, her total monthly cost would be:
\[
2,500 + 825 = 3,325 \text{ pesos}
\]

---

### Summary of Answers:

1. **6:** \( C(x) = 2,500 + 7.50x \)
2. **7:** \( x \leq 240 \)
3. **8:** 40 minutes
4. **9:** ₱2,650.00
5. **10:** ₱3,325.00

---

Let me know if you'd like more details or have any further questions!

Here are some follow-up questions related to this context:

1. How would the cost change if the charge per minute was reduced to ₱5?
2. What if Mariel used 500 minutes in one month? How much would her bill be?
3. What would the graph of the cost function \( C(x) \) look like?
4. How would her monthly bill be affected if the plan included 300 minutes instead of 240 minutes?
5. If Mariel used exactly 240 minutes every month, how much would she pay annually?

**Tip:** When working with cost functions, always check if the function has any constraints (e.g., included minutes) and adjust the formula accordingly.

Mariel wanted to avail a cellphone plan that offers a monthly fee of ₱2,500.00. It includes 240 minutes of call and charges ₱7.50 for each additional minute of usage. Solve questions 6-10 based on this scenario.

Learn how to calculate the cost of a cellphone plan with a base fee of ₱2,500 and additional charges of ₱7.50 per minute for calls exceeding 240 minutes. This problem involves linear functions and cost analysis, suitable for students in Grades 9-11.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation