Math Problem Statement

Solve for the magnitude of R if x is 6 m and y is 8.2 m.

Solution

The problem presents a right triangle with RR as the hypotenuse, x=6mx = 6 \, \text{m} as the base, and y=8.2my = 8.2 \, \text{m} as the height. To find the magnitude of RR, we can use the Pythagorean theorem:

R=x2+y2R = \sqrt{x^2 + y^2}

Now, substituting the values:

R=(6m)2+(8.2m)2R = \sqrt{(6 \, \text{m})^2 + (8.2 \, \text{m})^2}

Let me calculate that for you.The magnitude of RR is approximately 10.16m10.16 \, \text{m}.

Would you like further details or explanations? Here are some related questions:

  1. How can the Pythagorean theorem be used in different types of problems?
  2. What are the practical applications of this theorem in real-life scenarios?
  3. Can you find the angles of this triangle using trigonometry?
  4. How would you solve the problem if the hypotenuse RR and one side were given instead?
  5. How do units affect the accuracy and precision of measurements?

Tip: Always make sure to use consistent units when solving problems involving measurements.

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Math Problem Analysis

Mathematical Concepts

Geometry
Pythagorean Theorem

Formulas

R = sqrt(x^2 + y^2)

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 7-10