The given problem asks to solve for $h(x) = 3$ using the provided table of values.

Table Overview:

• The $x$-values: $-3, -2, -1, 0, 1, 2, 3$
• The $h(x)$-values: $3, 2, 3, 1, 4, -2, 0$

Step 1: Identify when $h(x) = 3$

From the table, we observe:

• When $x = -3$, $h(x) = 3$
• When $x = -1$, $h(x) = 3$

Step 2: Arrange the solutions

The two solutions for $h(x) = 3$ are $x_1 = -3$ and $x_2 = -1$, listed in ascending order.

So the answers are:

• $x_1 = -3$
• $x_2 = -1$

Would you like further clarification or more details? Here are 5 questions to expand the concept:

1. How would the solution change if you were asked to solve for $h(x) = 1$?
2. What is the domain and range of the function $h(x)$ as given by the table?
3. How would you interpret the meaning of $h(x) = -2$ using this table?
4. How would you graph the function based on the table values?
5. Can you determine if $h(x)$ is injective (one-to-one) from the table?

Tip: Always check the table values carefully to match the correct function value with its corresponding $x$-value when solving problems based on function tables.