To solve for $H$ from the equation $A = \frac{1}{2} B H$, you can follow these steps:

1. Start with the original equation: $A = \frac{1}{2} B H$

2. Multiply both sides by 2 to eliminate the fraction: $2A = B H$

3. Divide both sides by $B$ to isolate $H$: $H = \frac{2A}{B}$

So, the equation to find $H$ is: $H = \frac{2A}{B}$

Would you like more details on solving this, or do you have any other questions?

Here are five related questions:

1. How do you find the base $B$ given $A$ and $H$?
2. What is the formula for the area of a triangle?
3. Can this equation be used to solve for $A$ if $B$ and $H$ are known?
4. How do you handle cases where $B$ or $H$ equals zero?
5. What is the relationship between base and height in various types of triangles?

Tip: When solving for a variable, always perform the same operation on both sides of the equation to maintain equality.