To solve for \( H \) from the equation \( A = \frac{1}{2} B H \), you can follow these steps:

1. Start with the original equation:
   \[
   A = \frac{1}{2} B H
   \]

2. Multiply both sides by 2 to eliminate the fraction:
   \[
   2A = B H
   \]

3. Divide both sides by \( B \) to isolate \( H \):
   \[
   H = \frac{2A}{B}
   \]

So, the equation to find \( H \) is:
\[
H = \frac{2A}{B}
\]

Would you like more details on solving this, or do you have any other questions?

Here are five related questions:
1. How do you find the base \( B \) given \( A \) and \( H \)?
2. What is the formula for the area of a triangle?
3. Can this equation be used to solve for \( A \) if \( B \) and \( H \) are known?
4. How do you handle cases where \( B \) or \( H \) equals zero?
5. What is the relationship between base and height in various types of triangles?

**Tip:** When solving for a variable, always perform the same operation on both sides of the equation to maintain equality.

Learn how to solve for the height H in the area formula A = (1/2) B H with a step-by-step solution. This problem involves key concepts of algebra and geometry, suitable for students in Grades 6-8.

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