To solve the problem, we need to use some principles of geometry. Specifically, we'll apply the properties of angles formed by parallel lines and transversals.

Given:

• The roads AM and XY are parallel.
• $\angle BPQ = 70^\circ$.
• Angles $p$, $q$, $r$, $s$, and $t$ are also measured.

Since AM and XY are parallel, and BPQ seems to involve a transversal intersecting the parallel lines, the following rules are useful:

• Corresponding Angles: Angles on the same side of the transversal and in corresponding positions are equal.
• Alternate Interior Angles: Angles on opposite sides of the transversal but inside the parallel lines are equal.
• Co-interior (or Consecutive Interior) Angles: Angles on the same side of the transversal and inside the parallel lines add up to $180^\circ$.

For angle $p$:

• If $\angle BPQ$ is 70°, and angle $p$ is either a corresponding angle or an alternate interior angle to $\angle BPQ$, then $\angle p$ must also be $70^\circ$.

Hence, the correct answer is: b. 70°

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Do you want more details or have any questions?

Here are 5 related questions:

1. What is the measure of angle $q$ if it is a corresponding angle to $\angle BPQ$?
2. How would you calculate angle $r$ if it forms a straight line with $\angle BPQ$?
3. If $\angle s$ is an alternate interior angle to $\angle BPQ$, what is its measure?
4. Can you explain why alternate interior angles are equal when a transversal intersects two parallel lines?
5. How does the sum of angles on a straight line help determine unknown angles?

Tip: When dealing with parallel lines and transversals, remember the key relationships between corresponding, alternate interior, and co-interior angles. These rules are fundamental in solving such problems.