Math Problem Statement

Lös alla de här matte frågorna?

Lös alla de här matte frågorna?

Solution

Let's solve each problem step by step:

Question 8: Circle Geometry

In the figure, point MM is the center of the circle. The angles xx, yy, and a given angle of 5252^\circ are labeled. The goal is to find xx and yy.

Part (a): Find angle xx

  • Since MM is the center of the circle, the two segments from MM to the circumference are radii. This makes the triangle formed by these two radii an isosceles triangle.
  • The sum of the internal angles of a triangle is always 180180^\circ. Let's denote the angle at the center of the circle (where the radii meet) as θ\theta.
  • The angle opposite the 5252^\circ angle at the base of the isosceles triangle is also 5252^\circ.
  • Therefore, θ+52+52=180\theta + 52^\circ + 52^\circ = 180^\circ, so: θ=180104=76.\theta = 180^\circ - 104^\circ = 76^\circ. Thus, the central angle θ=76\theta = 76^\circ, and x=76x = 76^\circ.

Part (b): Find angle yy

  • yy is part of the cyclic quadrilateral formed inside the circle.
  • The sum of opposite angles in a cyclic quadrilateral is always 180180^\circ.
  • Given that one of the opposite angles is 5252^\circ, we have: y+52=180.y + 52^\circ = 180^\circ. Thus, y=18052=128y = 180^\circ - 52^\circ = 128^\circ.

Question 9: Right Triangle Check

We are given a triangle with sides 9 cm, 7 cm, and 6 cm. To check if the triangle is a right triangle, we can apply the Pythagorean theorem: a2+b2=c2,a^2 + b^2 = c^2, where aa and bb are the shorter sides, and cc is the hypotenuse (longest side).

Here, a=6a = 6 cm, b=7b = 7 cm, and c=9c = 9 cm. Let's check if this satisfies the Pythagorean theorem: 62+72=92,6^2 + 7^2 = 9^2, 36+49=81,36 + 49 = 81, 8581.85 \neq 81. Since the sides do not satisfy the Pythagorean theorem, this triangle is not a right triangle.


Summary of Solutions:

  • x=76x = 76^\circ
  • y=128y = 128^\circ
  • The triangle is not a right triangle.

Do you need further clarification or details on any of the steps?

Follow-up questions:

  1. What is the significance of opposite angles in a cyclic quadrilateral?
  2. How would you approach finding the area of the triangle in Question 9?
  3. Can you apply the Pythagorean theorem to any triangle? Why or why not?
  4. What is the relationship between the angles in an isosceles triangle?
  5. How does the central angle theorem help in solving circle-related problems?

Tip:

Always remember that the sum of the angles in any triangle is 180180^\circ. This is a crucial fact for solving geometric problems involving triangles.

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Math Problem Analysis

Mathematical Concepts

Circle Geometry
Cyclic Quadrilateral
Triangle Geometry
Pythagorean Theorem

Formulas

Sum of internal angles in a triangle = 180°
Opposite angles in a cyclic quadrilateral sum to 180°
Pythagorean theorem: a^2 + b^2 = c^2

Theorems

Cyclic Quadrilateral Theorem
Isosceles Triangle Property
Pythagorean Theorem

Suitable Grade Level

Grades 8-10