To find $(f \circ g)(x)$, we need to substitute $g(x)$ into $f(x)$.

Given:

• $f(x) = 2x + 1$
• $g(x) = 3x^2 + 5x - 2$

First, substitute $g(x)$ into $f(x)$:

$f(g(x)) = f(3x^2 + 5x - 2)$

Replace $x$ in $f(x)$ with $3x^2 + 5x - 2$:

$f(g(x)) = 2(3x^2 + 5x - 2) + 1$

Simplify:

$= 6x^2 + 10x - 4 + 1$

$= 6x^2 + 10x - 3$

So, $(f \circ g)(x) = 6x^2 + 10x - 3$.