Let the numerator of the fraction be $x$. According to the problem, the denominator exceeds the numerator by 25, so the denominator is $x + 25$.

The fraction is given as $\frac{3}{8}$. Therefore, we can set up the equation:

$\frac{x}{x+25} = \frac{3}{8}$

To solve for $x$, we can cross-multiply:

$8x = 3(x + 25)$

Expand the equation:

$8x = 3x + 75$

Now, subtract $3x$ from both sides:

$5x = 75$

Divide both sides by 5:

$x = 15$

Now that we have $x = 15$, the numerator is 15, and the denominator is $15 + 25 = 40$.

Thus, the fraction is:

$\frac{15}{40}$

This can be simplified:

$\frac{15}{40} = \frac{3}{8}$

Therefore, the original fraction is $\frac{15}{40}$.

Do you want more details or have any questions?

Here are some related questions:

1. How do you simplify fractions?
2. Can you explain the cross-multiplication method?
3. How do you check if two fractions are equivalent?
4. What are some other methods to solve fraction-related problems?
5. How do we know when a fraction can be simplified?

Tip: Always check if a fraction can be simplified by finding the greatest common divisor (GCD) of the numerator and denominator!