Math Problem Statement

The denominator of a fraction exceeds the numerator of a fraction by 25. The value of the is 3/8. Find the fraction

Solution

Let's solve this problem step by step.

Let the numerator of the fraction be xx.

Since the denominator exceeds the numerator by 25, the denominator will be x+25x + 25.

The value of the fraction is given as 38\frac{3}{8}.

Thus, we can set up the equation as: xx+25=38\frac{x}{x + 25} = \frac{3}{8}

To solve for xx, cross-multiply: 8x=3(x+25)8x = 3(x + 25)

Now, distribute the 3 on the right side: 8x=3x+758x = 3x + 75

Next, subtract 3x3x from both sides to isolate xx on one side: 5x=755x = 75

Now, divide both sides by 5 to solve for xx: x=15x = 15

So, the numerator of the fraction is 15.

The denominator, which is x+25x + 25, will be: 15+25=4015 + 25 = 40

Thus, the fraction is: 1540\frac{15}{40}

We can simplify this fraction by dividing both the numerator and denominator by their greatest common divisor, which is 5: 15÷540÷5=38\frac{15 \div 5}{40 \div 5} = \frac{3}{8}

Therefore, the fraction is 1540\frac{15}{40}.

Would you like to go over any details, or do you have any questions?

Here are 5 related questions you might find interesting:

  1. How do you find the least common denominator between two fractions?
  2. What is the process for adding fractions with different denominators?
  3. How do you simplify complex fractions?
  4. Can a fraction be greater than 1? If so, give an example.
  5. How do you convert an improper fraction to a mixed number?

Tip: When working with fractions, always check if the final answer can be simplified by finding the greatest common divisor of the numerator and denominator.