Math Problem Statement

Solve the X?

Solution

To solve for xx, let's analyze the given diagram.

Analysis:

  1. The diagram shows a semicircle with a diameter labeled as 4+x+1=x+54 + x + 1 = x + 5.
  2. Inside the semicircle, there's a circle tangent to the diameter and the semicircle itself.
  3. The distance 44 and 11 are the segments from the center of the semicircle to where the semicircle meets the diameter on either side of the circle.

Steps to solve:

  1. Identify the radius of the semicircle:

    • The total diameter of the semicircle is x+5x + 5, so the radius RR of the semicircle is R=x+52R = \frac{x + 5}{2}.
  2. Determine the radius rr of the inner circle:

    • The radius of the inner circle will be equal to RR minus the distance from the center of the semicircle to the point of tangency on the diameter. This distance is half of 4+14 + 1, so it is 52=2.5\frac{5}{2} = 2.5.
    • Therefore, the radius rr of the inner circle is RrR - r.
  3. Set up the equation:

    • Since the inner circle is tangent to the semicircle and the diameter, the distance from the center of the semicircle to the center of the inner circle is RrR - r.
    • The radius rr is also equal to R(R2.5)R - (R - 2.5).

    This results in the equation: r=R2.5r = R - 2.5

  4. Substitute R=x+52R = \frac{x + 5}{2} into the equation: r=x+522.5r = \frac{x + 5}{2} - 2.5

  5. Solve for rr and match with the geometry: The radius rr is determined by the conditions of the problem, such as the circle fitting perfectly inside the semicircle with tangency.

    Therefore, we simplify and solve the equation: x+522.5=r\frac{x + 5}{2} - 2.5 = r The radius of the inner circle rr is calculated by the tangency condition.

Given the information, the equation simplifies to determine xx.

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Math Problem Analysis

Mathematical Concepts

Geometry
Circle Geometry
Tangents
Semicircles

Formulas

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Theorems

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Suitable Grade Level

Advanced High School