From the images, it appears that you are working on a differential equation and you want to find $x$ when $y = \frac{-1}{4}x + \frac{5}{4}$.

To solve this, we'll first need to solve the differential equation. However, it looks like the second image might be an equation that connects with this function, but the context is unclear.

Let me break it down:

1. First step: You have a linear equation $y = \frac{-1}{4}x + \frac{5}{4}$, so if you're looking to find the value of $x$ when $y$ takes a specific value, we can use this equation directly.

2. Substituting: If you want to find $x$ when $y = 0$, you would set the equation equal to 0: $0 = \frac{-1}{4}x + \frac{5}{4}$

   Solve for $x$: $\frac{1}{4}x = \frac{5}{4}$

   Multiply both sides by 4: $x = 5$

So, if you're asking to find $x$ when $y = 0$, then $x = 5$.

If you're looking to solve for $x$ in a different context with the differential equation, please let me know what you need and if you want me to clarify anything further.

Would you like more details on solving this problem, or is there another specific part of the equation you need help with?

Other questions you could explore:

1. How do I solve a first-order linear differential equation?
2. What is the general solution to a differential equation?
3. How do you manipulate linear equations to find solutions?
4. What are some methods to solve for particular solutions in a differential equation?
5. How do you interpret solutions from a differential equation in context?

Tip: When solving for $x$ in linear equations, isolating the variable on one side and simplifying will lead you directly to the solution.