This is a triangle problem where you are asked to solve for $x$.

Solution Steps:

In a triangle, the sum of the interior angles is always $180^\circ$. The angles given are:

• $70^\circ$,
• $63^\circ$,
• The remaining angle is represented as $x + 56^\circ$.

To solve for $x$, set up the equation using the fact that the sum of the angles in a triangle is $180^\circ$:

$70^\circ + 63^\circ + (x + 56^\circ) = 180^\circ$

Now, combine the constants on the left-hand side:

$133^\circ + x + 56^\circ = 180^\circ$

Simplify further:

$189^\circ + x = 180^\circ$

Now, solve for $x$:

$x = 180^\circ - 189^\circ$ $x = -9^\circ$

Thus, $x = -9^\circ$.

Let me know if you'd like further clarification or additional details!

Related Questions:

1. What are the interior angles of an equilateral triangle?
2. How do you solve for angles in an isosceles triangle?
3. What is the exterior angle theorem in triangles?
4. How do you prove that the sum of the angles in any triangle is $180^\circ$?
5. How do you calculate the angles of a triangle given two sides and one angle?

Tip:

When solving for angles, always double-check that the sum of the angles adds up to $180^\circ$ to avoid errors!