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The image presents a current junction with five currents: \( I_1, I_2, I_3, I_4, \) and \( I_5 \), where some current values are given, and the goal is to determine \( I_3 \). The problem specifies:

- \( I_1 = I_4 = 6A \)
- \( I_2 = I_5 = 3A \)

By applying Kirchhoff's Current Law (KCL), which states that the sum of currents entering a junction equals the sum of currents leaving the junction, we have:

\[
I_1 + I_2 = I_3 + I_4 + I_5
\]

Substitute the known values:

\[
6A + 3A = I_3 + 6A + 3A
\]

Simplifying:

\[
9A = I_3 + 9A
\]

So,

\[
I_3 = 0A
\]

However, since there are no options for \( 0A \), it might be a mistake in interpreting the directions of the currents in the diagram. Do you need more details or further clarification?

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Here are five related questions to deepen understanding:

1. How would reversing the direction of one current affect the calculation?
2. What is Kirchhoff's Voltage Law, and how does it complement Kirchhoff's Current Law?
3. Could resistances be included in the calculation for more complexity?
4. How does the junction rule apply to alternating current (AC)?
5. What is the difference between node and mesh analysis in circuit theory?

**Tip:** Always check the direction of current flow before applying Kirchhoff’s laws, as incorrect assumptions can lead to errors in the results.

Diketahui gambar sebagai berikut. Jika I1 = I4 = 6A dan I2 = I5 = 3A. Maka besar I3 adalah?

This circuit analysis problem involves solving for I3 using Kirchhoff's Current Law. Given that I1 = I4 = 6A and I2 = I5 = 3A, students apply the junction rule to determine the unknown current. The solution is suitable for students in Grades 10-12 and emphasizes current analysis in circuits.

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