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You are asked to solve the formula for \( b_2 \) from the area of a trapezoid formula:

\[
A = \frac{1}{2} h (b_1 + b_2)
\]

Let's solve for \( b_2 \).

### Steps:

1. Start with the formula:
   \[
   A = \frac{1}{2} h (b_1 + b_2)
   \]

2. Multiply both sides by 2 to eliminate the fraction:
   \[
   2A = h (b_1 + b_2)
   \]

3. Divide both sides by \( h \) to isolate \( b_1 + b_2 \):
   \[
   \frac{2A}{h} = b_1 + b_2
   \]

4. Finally, subtract \( b_1 \) from both sides to solve for \( b_2 \):
   \[
   b_2 = \frac{2A}{h} - b_1
   \]

Thus, the formula for \( b_2 \) is:
\[
b_2 = \frac{2A}{h} - b_1
\]

Would you like any further details on this solution?

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Here are 5 related questions:
1. How do you calculate the area of a trapezoid if \( A \), \( h \), and \( b_1 \) are known?
2. What is the meaning of the variables in the trapezoid area formula?
3. How does the height \( h \) influence the area of a trapezoid?
4. How can you apply this formula to irregular trapezoidal shapes?
5. What is the difference between calculating the area of a trapezoid versus a triangle?

**Tip:** Always make sure the units for height and the bases are the same before performing calculations.

Solve the formula for b_2. Area of a trapezoid: A = (1/2) h (b_1 + b_2).

Learn how to solve for b2 using the area of a trapezoid formula: A = (1/2) h (b_1 + b_2). This tutorial breaks down the algebraic steps involved, providing a detailed explanation for students in Grades 8-10.

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