Let's solve the formula for \( b_1 \) instead of \( b_2 \).

The given formula is:

\[
A = \frac{1}{2} h (b_1 + b_2)
\]

### Step-by-Step Solution to Solve for \( b_1 \):

1. **Start with the given equation:**

   \[
   A = \frac{1}{2} h (b_1 + b_2)
   \]

2. **Multiply both sides by 2 to eliminate the fraction:**

   \[
   2A = h (b_1 + b_2)
   \]

3. **Divide both sides by \( h \) to solve for \( b_1 + b_2 \):**

   \[
   \frac{2A}{h} = b_1 + b_2
   \]

4. **Subtract \( b_2 \) from both sides to isolate \( b_1 \):**

   \[
   b_1 = \frac{2A}{h} - b_2
   \]

So, the formula solved for \( b_1 \) is:

\[
b_1 = \frac{2A}{h} - b_2
\]

Would you like further details or have any questions?

Here are 5 related questions you might find useful:
1. How would you solve for \( h \) in the same equation?
2. How would you interpret the values of \( b_1 \) and \( b_2 \) if they are equal?
3. What happens to the area \( A \) if \( b_1 \) increases while \( b_2 \) and \( h \) remain constant?
4. Can you derive a formula to find \( b_1 \) if \( A \) is known but \( h \) is unknown?
5. How does this formula apply to specific trapezoid problems in geometry?

**Tip:** Always double-check which variable you need to isolate, as small changes in your target variable can lead to different solutions.

Learn how to solve for b1 in the formula for the area of a trapezoid, A = 1/2 * h * (b1 + b2). This problem involves understanding the geometry of trapezoids and the application of the area formula. Suitable for high school students in Grades 9-12.

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