Math Problem Statement

Solve for x. Round to the nearest tenth of a degree, if necessary.

Solution

The image shows a right triangle JIH\triangle JIH, with side lengths JI=54JI = 54 and HI=44HI = 44, and an angle xx^\circ at JJ. We are asked to find the value of xx^\circ, which is the angle at vertex JJ.

To solve for xx, we can use trigonometric ratios, specifically the tangent function because we are given the lengths of the opposite side (44) and the adjacent side (54) relative to xx.

The tangent of an angle in a right triangle is given by: tan(x)=oppositeadjacent=HIJI\tan(x) = \frac{\text{opposite}}{\text{adjacent}} = \frac{HI}{JI}

Substitute the given values: tan(x)=4454\tan(x) = \frac{44}{54}

Now calculate the ratio: tan(x)0.8148\tan(x) \approx 0.8148

To find xx, we take the inverse tangent (arctangent) of 0.8148: x=tan1(0.8148)x = \tan^{-1}(0.8148)

Using a calculator: x39.0x \approx 39.0^\circ

Thus, the angle xx is approximately 39.039.0^\circ, rounded to the nearest tenth.

Would you like more details on this solution or further explanation on any steps?

Here are five related questions to expand on this:

  1. How do you find the other angle of the triangle?
  2. What is the sine of angle xx?
  3. How do you calculate the hypotenuse using the Pythagorean theorem?
  4. How can we verify the angle xx using the cosine function?
  5. What is the general relationship between trigonometric ratios in right triangles?

Tip: Always double-check your rounding when working with degrees to ensure accuracy, especially when asked to round to the nearest tenth.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Right Triangles
Inverse Tangent

Formulas

tan(x) = opposite/adjacent
x = tan^(-1)(opposite/adjacent)

Theorems

Pythagorean Theorem
Trigonometric Ratios

Suitable Grade Level

Grades 9-10