Math Problem Statement

b/a+c/b=1/ab solve for a

Solution

We are given the equation:

ba+cb=1ab\frac{b}{a} + \frac{c}{b} = \frac{1}{ab}

Let's solve for aa.

Step 1: Eliminate denominators

Multiply through the equation by abab to eliminate the denominators. This gives:

ab(ba+cb)=ab1abab \cdot \left( \frac{b}{a} + \frac{c}{b} \right) = ab \cdot \frac{1}{ab}

Step 2: Simplify each term

For the left-hand side:

abba=b2,abcb=acab \cdot \frac{b}{a} = b^2, \quad ab \cdot \frac{c}{b} = ac

For the right-hand side:

ab1ab=1ab \cdot \frac{1}{ab} = 1

Now the equation becomes:

b2+ac=1b^2 + ac = 1

Step 3: Solve for aa

Rearrange the equation to solve for aa:

ac=1b2ac = 1 - b^2

Now, divide both sides by cc to isolate aa:

a=1b2ca = \frac{1 - b^2}{c}

Final Answer:

a=1b2ca = \frac{1 - b^2}{c}

Let me know if you want more details on the solution or have any other questions! Here are some related questions:

  1. How would the solution change if the equation had a different constant instead of 1 on the right-hand side?
  2. Can we solve for bb instead of aa in the same equation?
  3. How would we handle this problem if c=0c = 0?
  4. What is the geometric interpretation of this equation if we assign physical meaning to aa, bb, and cc?
  5. How do we solve equations like this when they involve more complex terms, like higher powers or square roots?

Tip: Always check if you can simplify the equation by eliminating fractions early on—this makes solving much easier!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Rational Equations
Fraction Manipulation

Formulas

b/a + c/b = 1/ab
a = (1 - b^2) / c

Theorems

Basic properties of algebraic manipulation
Fraction elimination by multiplication

Suitable Grade Level

Grades 9-12