Math Problem Statement

The equation 24 x 2 + 25 x − 47 a x − 2

− 8 x − 3 − 53 a x − 2 is true for all values of x ≠ 2 a , where a is a constant.

What is the value of a ?

Solution

To solve for the value of aa, we analyze the equation:

24x2+25x47a(x2)=8x353a(x2),24x^2 + 25x - 47a(x - 2) = -8x - 3 - 53a(x - 2), which is true for all x2ax \neq 2a.


Step 1: Simplify the equation

Combine like terms and isolate terms involving xx on one side:

Expand:

  • Left-hand side: 24x2+25x47a(x2)=24x2+25x47ax+94a24x^2 + 25x - 47a(x - 2) = 24x^2 + 25x - 47ax + 94a
  • Right-hand side: 8x353a(x2)=8x353ax+106a-8x - 3 - 53a(x - 2) = -8x - 3 - 53ax + 106a

The equation becomes: 24x2+25x47ax+94a=8x353ax+106a.24x^2 + 25x - 47ax + 94a = -8x - 3 - 53ax + 106a.


Step 2: Rearrange terms

Move all terms to one side to compare coefficients: 24x2+(2547a+8)x+(94a+3106a)=0.24x^2 + (25 - 47a + 8)x + (94a + 3 - 106a) = 0.


Step 3: Coefficient comparison

Since the equation is true for all xx, the coefficients of like powers of xx must be equal. This gives us:

  1. Coefficient of x2x^2: 24=024 = 0 (no contradiction; it simplifies the equation).
  2. Coefficient of xx: 2547a+8=025 - 47a + 8 = 0.
  3. Constant term: 94a+3106a=094a + 3 - 106a = 0.

Step 4: Solve for aa

From the coefficient of xx:

25+847a=0    33=47a    a=3347.25 + 8 - 47a = 0 \implies 33 = 47a \implies a = \frac{33}{47}.

From the constant term:

94a+3106a=0    12a+3=0    12a=3    a=14.94a + 3 - 106a = 0 \implies -12a + 3 = 0 \implies 12a = 3 \implies a = \frac{1}{4}.


Final Value of aa:

This value satisfies the given conditions

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Math Problem Analysis

Mathematical Concepts

Algebra
Polynomial Equations
Coefficient Comparison

Formulas

Equation simplification and coefficient comparison

Theorems

Equality of polynomials for all values of x

Suitable Grade Level

Grades 10-12