To solve for \( a \) in the equation \( na + m = 20 \):

1. **Subtract \( m \) from both sides** of the equation to isolate the term involving \( a \):

\[
na = 20 - m
\]

2. **Divide both sides** of the equation by \( n \) to solve for \( a \):

\[
a = \frac{20 - m}{n}
\]

So, the solution for \( a \) is:

\[
a = \frac{20 - m}{n}
\]

Would you like more details or have any questions?

Here are 5 related questions:

1. How would you solve for \( m \) in the equation \( na + m = 20 \)?
2. What happens to \( a \) when \( n = 0 \) in the original equation?
3. Can you solve for \( n \) in the equation \( na + m = 20 \)?
4. How would you graph the function \( a(n) = \frac{20 - m}{n} \)?
5. What is the domain of the function \( a(n) = \frac{20 - m}{n} \)?

**Tip:** Always check for any restrictions on the variable after solving the equation, especially when dealing with fractions.

Learn how to solve for a in the linear equation na + m = 20 with a detailed step-by-step solution. This problem covers key algebraic concepts, including equation solving formula. Suitable for students in Grades 7-9.

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