Math Problem Statement

10−(3) SQUARED ÷(6−3)⋅1

Solution

Let's break down the expression step by step:

The given expression is:

10(3)2÷(63)110 - (3)^2 \div (6 - 3) \cdot 1

Step 1: Solve the parentheses

We start by simplifying the terms inside the parentheses.

63=36 - 3 = 3

The expression now becomes:

10(3)2÷3110 - (3)^2 \div 3 \cdot 1

Step 2: Solve the exponent

Next, evaluate (3)2(3)^2, which means 32=93^2 = 9.

Now the expression looks like:

109÷3110 - 9 \div 3 \cdot 1

Step 3: Division and multiplication (left to right)

According to the order of operations (PEMDAS/BODMAS), we handle division and multiplication from left to right.

  1. 9÷3=39 \div 3 = 3

Now the expression is:

103110 - 3 \cdot 1

  1. 31=33 \cdot 1 = 3

Now the expression is:

10310 - 3

Step 4: Subtraction

Finally, subtract:

103=710 - 3 = 7

Final Answer:

The result of the expression is 7\boxed{7}.

Would you like more details or have any questions?

Here are 5 related questions for further practice:

  1. What is 15(4)2÷(84)215 - (4)^2 \div (8 - 4) \cdot 2?
  2. How would the expression change if the exponent was (4)2(4)^2 instead of (3)2(3)^2?
  3. Solve 20(5)2÷(72)320 - (5)^2 \div (7 - 2) \cdot 3.
  4. What happens if you change the multiplication to addition in the expression?
  5. What if we switch the order of operations by removing parentheses?

Tip: Always remember the order of operations: parentheses, exponents, multiplication and division (left to right), addition and subtraction (left to right).

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Math Problem Analysis

Mathematical Concepts

Arithmetic
Order of Operations (PEMDAS/BODMAS)
Exponents
Basic Algebra

Formulas

Order of operations: Parentheses → Exponents → Multiplication/Division → Addition/Subtraction

Theorems

None explicitly, but uses the PEMDAS/BODMAS rule for solving expressions

Suitable Grade Level

Grades 6-8