Let's break down the expression step by step:

The given expression is:

\[
10 - (3)^2 \div (6 - 3) \cdot 1
\]

### Step 1: Solve the parentheses
We start by simplifying the terms inside the parentheses.

\[
6 - 3 = 3
\]

The expression now becomes:

\[
10 - (3)^2 \div 3 \cdot 1
\]

### Step 2: Solve the exponent
Next, evaluate \( (3)^2 \), which means \( 3^2 = 9 \).

Now the expression looks like:

\[
10 - 9 \div 3 \cdot 1
\]

### Step 3: Division and multiplication (left to right)
According to the order of operations (PEMDAS/BODMAS), we handle division and multiplication from left to right.

1. \( 9 \div 3 = 3 \)
   
Now the expression is:

\[
10 - 3 \cdot 1
\]

2. \( 3 \cdot 1 = 3 \)

Now the expression is:

\[
10 - 3
\]

### Step 4: Subtraction
Finally, subtract:

\[
10 - 3 = 7
\]

### Final Answer:
The result of the expression is \( \boxed{7} \).

Would you like more details or have any questions?

Here are 5 related questions for further practice:
1. What is \( 15 - (4)^2 \div (8 - 4) \cdot 2 \)?
2. How would the expression change if the exponent was \( (4)^2 \) instead of \( (3)^2 \)?
3. Solve \( 20 - (5)^2 \div (7 - 2) \cdot 3 \).
4. What happens if you change the multiplication to addition in the expression?
5. What if we switch the order of operations by removing parentheses?

**Tip:** Always remember the order of operations: parentheses, exponents, multiplication and division (left to right), addition and subtraction (left to right).

Learn how to solve the arithmetic expression 10−(3)^2 ÷(6−3)⋅1 step-by-step using the order of operations (PEMDAS/BODMAS). This problem covers basic algebraic concepts like exponents, division, and subtraction, suitable for students in Grades 6-8.

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