Let's solve the equation $x + 2(3 - x) = 4x - 4$.

Step 1: Distribute the 2 on the left side

$x + 2 \cdot 3 - 2 \cdot x = 4x - 4$ $x + 6 - 2x = 4x - 4$

Step 2: Combine like terms on the left side

$(1x - 2x) + 6 = 4x - 4$ $-x + 6 = 4x - 4$

Step 3: Move all the terms involving $x$ to one side and constants to the other side

Add $x$ to both sides: $6 = 5x - 4$

Step 4: Isolate the term with $x$

Add 4 to both sides: $10 = 5x$

Step 5: Solve for $x$

Divide both sides by 5: $x = 2$

The solution is $x = 2$.

Would you like more details on any step, or do you have any questions?

Here are 5 related questions you might find interesting:

1. How do you solve the equation $2(x + 4) = 3x + 8$?
2. What is the solution to $4 - 3(x + 2) = x - 8$?
3. How can you solve $2(3y - 5) + y = 4y + 7$?
4. What steps are involved in solving $5(x - 1) - 2x = 3x + 10$?
5. How do you simplify and solve $x + 3(2x - 1) = 5x + 2$?

Tip: When combining like terms, make sure to carefully consider the signs of each term to avoid mistakes.