Solve Upper W equals 2 YZ plus 2 YX plus 2 ZX for Upper X.

We are given the equation:

\[
W = 2YZ + 2YX + 2ZX
\]

To solve for \( X \), let's follow these steps:

### Step 1: Isolate terms containing \( X \)
We can factor out the common term involving \( X \) from the right-hand side:

\[
W = 2YZ + 2X(Y + Z)
\]

### Step 2: Move the non-\( X \) term to the other side
Subtract \( 2YZ \) from both sides of the equation:

\[
W - 2YZ = 2X(Y + Z)
\]

### Step 3: Solve for \( X \)
Divide both sides by \( 2(Y + Z) \) to isolate \( X \):

\[
X = \frac{W - 2YZ}{2(Y + Z)}
\]

Thus, the solution for \( X \) is:

\[
X = \frac{W - 2YZ}{2(Y + Z)}
\]

Would you like a detailed breakdown of each step, or do you have any other questions?

### Related Questions:
1. What happens if \( Y + Z = 0 \)?
2. How can this equation be applied in practical scenarios?
3. What is the physical interpretation if \( W \), \( X \), \( Y \), and \( Z \) represent forces?
4. How would the solution change if additional constraints on \( W \), \( Y \), or \( Z \) were given?
5. What if instead of constants, \( W \), \( Y \), and \( Z \) were functions of another variable?

### Tip:
When solving for a variable, always check for conditions that could make the denominator zero, as this could indicate restrictions on the solution.

Learn how to solve the equation W = 2YZ + 2YX + 2ZX for X step-by-step with detailed explanations and examples. This problem involves algebraic manipulation and factorization techniques. Suitable for advanced high school students.

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