Let's break down and solve the equation step by step.

The image presents the following equation:

$\triangle \cdot \bigcirc + 6 + \bigcirc \cdot 6 + \triangle = 1 \triangle 63$

Where:

• $\triangle$ and $\bigcirc$ represent unknown numbers.
• $1\triangle 63$ means that $\triangle$ is in the tens place (e.g., if $\triangle = 7$, this would be $763$).

Step 1: Interpret the equation

We can rewrite the equation as:

$\triangle \cdot \bigcirc + 6 + \bigcirc \cdot 6 + \triangle = 100 + \triangle \cdot 10 + 63$

(The term $1\triangle 63$ means $100 + 10 \cdot \triangle + 63$).

Step 2: Simplify the right-hand side

$100 + 63 + 10 \cdot \triangle = 163 + 10 \cdot \triangle$

So the full equation becomes:

$\triangle \cdot \bigcirc + 6 + \bigcirc \cdot 6 + \triangle = 163 + 10 \cdot \triangle$

Step 3: Guess and check method

Now, we will try different values for $\triangle$ and $\bigcirc$ from the answer options and see which one satisfies the equation.

Testing option $B$: \triangle = 7), $\bigcirc = 7$

$7 \cdot 7 + 6 + 7 \cdot 6 + 7 = 163 + 70$

Simplifying:

$49 + 6 + 42 + 7 = 233$

But the right-hand side is:

$163 + 70 = 233$

Since both sides are equal, $\triangle = 7$ and $\bigcirc = 7$ is correct.

Step 4: Calculate $\bigcirc - \triangle$

Now, we need to compute:

$\bigcirc - \triangle = 7 - 7 = 0$

So the correct answer is 0. However, this answer is not part of the multiple-choice options provided.