Solve the following equation.

u Superscript 5 Baseline equals 243u5=243

To solve the equation:

\[
u^5 = 243
\]

we need to isolate \( u \). To do this, take the fifth root of both sides of the equation:

\[
u = \sqrt[5]{243}
\]

Now, we compute the fifth root of 243:

\[
u = 3
\]

Thus, the solution to the equation is:

\[
u = 3
\]

Would you like further details or have any questions?

Here are five related questions for practice:
1. Solve \( x^5 = 1024 \).
2. What is \( u^4 = 81 \)?
3. Solve \( u^3 = 27 \).
4. Solve \( u^6 = 729 \).
5. What is \( u^2 = 16 \)?

**Tip:** The nth root of a number can be computed as the inverse of raising the number to the nth power.

Learn how to solve the equation u^5 = 243 with a detailed solution. This problem demonstrates key concepts in algebra, exponentiation, and the use of roots. Suitable for students in Grades 8-10, it covers solving for variables raised to a power and finding roots.

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