Math Problem Statement

Solve e^x^2=1

Solution

To solve the equation ex2=1e^{x^2} = 1, we need to find the values of xx that satisfy this equation.

The exponential function eye^y equals 1 when y=0y = 0, because e0=1e^0 = 1.

Given ex2=1e^{x^2} = 1, we can write:

x2=0x^2 = 0

Taking the square root of both sides, we get:

x=0x = 0

Therefore, the solution to the equation ex2=1e^{x^2} = 1 is:

x=0x = 0

Would you like more details or have any questions?

Here are some related questions:

  1. What is the value of xx in ex=1e^x = 1?
  2. How do you solve ex2=ke^{x^2} = k for a general constant kk?
  3. What are the properties of the exponential function exe^x?
  4. Can ex2=1e^{x^2} = 1 have any complex solutions?
  5. What are the solutions to ex2=1e^{x^2} = -1?
  6. How would you graph the function ex2e^{x^2}?
  7. What happens to ex2e^{x^2} as xx approaches infinity?
  8. How do you solve ex2=ee^{x^2} = e where ee is the base of the natural logarithm?

Tip: Remember that the exponential function exe^x is always positive and never zero.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Exponential Functions

Formulas

Exponential function: e^x

Theorems

-

Suitable Grade Level

Grades 10-12