It looks like you've written the same equation twice. I will assume you meant to write it once. Let's solve the equation:

\[
3x - 20 = 7
\]

### Steps to Solve:

1. **Add 20 to both sides** to get rid of the constant term on the left side:
   \[
   3x - 20 + 20 = 7 + 20
   \]
   \[
   3x = 27
   \]

2. **Divide both sides by 3** to solve for \(x\):
   \[
   \frac{3x}{3} = \frac{27}{3}
   \]
   \[
   x = 9
   \]

### Solution:
\[
x = 9
\]

Would you like more details, or do you have any questions?

### Related Questions:
1. How do you solve for \(x\) in the equation \(5x - 10 = 20\)?
2. What is the next step if the equation was \(4x - 10 = 30\)?
3. How do you check if your solution to a linear equation is correct?
4. What happens if both sides of the equation have the variable, like \(2x + 3 = x + 8\)?
5. How do you solve the equation \(7x + 14 = 0\)?
6. What is the solution to \(8x - 24 = 0\)?
7. How would you solve the equation \(x/4 - 5 = 3\)?
8. How does solving equations change if you introduce fractions?

**Tip:** Always double-check your work by substituting the solution back into the original equation to see if it holds true.

Learn how to solve the linear equation 3x - 20 = 7 with detailed step-by-step instructions. This problem covers basic algebraic concepts such as solving linear equations. Suitable for students in Grades 7-9.

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