To solve for \(x\) in the equation \(7x + 3x + 20 = 0\):

1. Combine the like terms on the left side:
\[
7x + 3x = 10x
\]
So the equation becomes:
\[
10x + 20 = 0
\]

2. Subtract 20 from both sides:
\[
10x = -20
\]

3. Divide both sides by 10 to isolate \(x\):
\[
x = \frac{-20}{10}
\]
\[
x = -2
\]

The solution is \(x = -2\).

Would you like further details on any step? Here are some related questions for further exploration:

1. How would the solution change if the equation was \(7x + 3x - 20 = 0\)?
2. Can you graph the equation \(7x + 3x + 20 = 0\)?
3. What happens when you multiply both sides of the equation by 2?
4. How would you solve this if the equation had a quadratic term, like \(7x^2 + 3x + 20 = 0\)?
5. Can you solve a similar equation where the coefficients are fractions?

**Tip**: Always combine like terms first when solving linear equations to simplify your work.

Learn how to solve the linear equation 7x + 3x + 20 with a step-by-step breakdown. This solution simplifies the equation, combines like terms, and isolates the variable x. Suitable for students in Grades 6-8, this problem helps build core algebra skills.

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