To solve the equation \( x \times 2 = 81 \), we need to isolate \( x \). Here's the solution:

\[
2x = 81
\]

To find \( x \), divide both sides of the equation by 2:

\[
x = \frac{81}{2}
\]

\[
x = 40.5
\]

So, the solution is \( x = 40.5 \).

Would you like any further explanation or details on this solution? Here are some related questions for further exploration:

1. What is the result of \( 3x = 81 \)?
2. How would you solve the equation \( x \div 2 = 81 \)?
3. If \( 2x + 5 = 81 \), what is the value of \( x \)?
4. What is the result of multiplying the solution \( x = 40.5 \) by 3?
5. How do you solve the equation \( x - 2 = 81 \)?
6. What is the reciprocal of the solution \( x = 40.5 \)?
7. How would the solution change if the equation was \( 2x = 80 \) instead of \( 81 \)?
8. How do you solve the equation \( 4x = 81 \)?

**Tip:** When solving equations, always perform the same operation on both sides of the equation to maintain equality.

Learn how to solve the equation 2x = 81 with a detailed step-by-step solution. This problem covers key algebraic concepts such as equations, division, and multiplication. Suitable for students in Grades 6-8.

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