To solve the equation:

\[
7c + 4c - 16 = 6,
\]

we first combine like terms on the left-hand side. The terms \(7c\) and \(4c\) are like terms:

\[
(7c + 4c) - 16 = 6.
\]

Combining \(7c\) and \(4c\) gives:

\[
11c - 16 = 6.
\]

Next, add 16 to both sides to isolate the term with \(c\):

\[
11c = 6 + 16,
\]

\[
11c = 22.
\]

Now, divide both sides by 11 to solve for \(c\):

\[
c = \frac{22}{11},
\]

\[
c = 2.
\]

Thus, the solution is:

\[
\boxed{c = 2}.
\]

Would you like more details or have any questions?

Here are some related questions to consider:

1. How would the solution change if the equation was \(7c + 4c - 16 = 0\)?
2. What are the steps to combine like terms in an algebraic expression?
3. How can you verify the solution to this equation?
4. What would happen if we have \(7c - 4c - 16 = 6\)?
5. How can this equation be represented graphically, and what does the solution represent?

**Tip:** Always combine like terms to simplify an equation before solving for the variable.

Learn how to solve the equation 7c + 4c - 16 = 6 with a detailed step-by-step solution. This problem involves combining like terms and isolating the variable to find the solution, suitable for students in Grades 7-9.

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