Math Problem Statement

. If π‘₯ x varies directly as 𝑦 y and π‘₯

35 x=35 and 𝑦

7 y=7, what is the value of 𝑦 y when π‘₯

25?

Solution

Since xx varies directly as yy, we can express this relationship as:

x=kβ‹…yx = k \cdot y

where kk is the constant of proportionality.

Step 1: Find the constant kk

Given that x=35x = 35 when y=7y = 7, we can substitute these values into the equation:

35=kβ‹…735 = k \cdot 7

Solving for kk:

k=357=5k = \frac{35}{7} = 5

Step 2: Use the constant kk to find yy when x=25x = 25

Now, we can use the equation x=5β‹…yx = 5 \cdot y and substitute x=25x = 25:

25=5β‹…y25 = 5 \cdot y

Solving for yy:

y=255=5y = \frac{25}{5} = 5

Thus, the value of yy when x=25x = 25 is y=5y = 5.


Would you like further details or clarifications on any step?

Related Questions:

  1. How would you solve if xx varies inversely with yy?
  2. What happens if both xx and yy vary directly with another variable?
  3. How would the equation change if xx varied as the square of yy?
  4. Can you find yy if x=50x = 50 under the same direct variation rule?
  5. What if y=10y = 10 and you needed to find xx?

Tip:

For direct variation problems, remember that the ratio xy\frac{x}{y} remains constant.

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Math Problem Analysis

Mathematical Concepts

Direct Variation
Proportions
Algebra

Formulas

x = k * y
y = x / k

Theorems

Direct Variation Theorem

Suitable Grade Level

Grades 6-8