The cube root of a number, increased by four is six. 

Let's define the unknown number as \( x \). 

According to the problem, the cube root of the number, increased by four, equals six. We can write this as the equation:

\[
\sqrt[3]{x} + 4 = 6
\]

To solve for \( x \), follow these steps:

1. Subtract 4 from both sides:

\[
\sqrt[3]{x} = 6 - 4
\]
\[
\sqrt[3]{x} = 2
\]

2. Now, cube both sides to eliminate the cube root:

\[
x = 2^3
\]
\[
x = 8
\]

So, the number is \( x = 8 \).

Would you like further details or explanations?

Here are five related questions to expand your understanding:

1. What is the cube root of \( 27 \) plus 3?
2. If the cube root of a number increased by 5 is 10, what is the number?
3. How would you solve the equation \( \sqrt[3]{x + 2} = 4 \)?
4. Can you find the cube of a negative number, for example, \( (-3)^3 \)?
5. How do cube roots differ from square roots in terms of solving equations?

**Tip:** When solving equations involving cube roots, remember that the cube root of a negative number is negative!

The cube root of a number, increased by four is six.

Learn how to solve the equation involving the cube root of a number increased by 4 equals 6. This problem covers cube root concepts and solving algebraic equations step-by-step. Suitable for students in Grades 6-8.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation