Math Problem Statement

Solve the inequality: cube root of (x + 7) ≥ 3.

Solution

The inequality presented in the image is:

x+733\sqrt[3]{x + 7} \geq 3

Step-by-Step Solution:

  1. Eliminate the Cube Root: To isolate x+7x + 7, cube both sides of the inequality: (x+73)333\left(\sqrt[3]{x + 7}\right)^3 \geq 3^3 This simplifies to: x+727x + 7 \geq 27

  2. Isolate xx: Subtract 7 from both sides: x277x \geq 27 - 7 x20x \geq 20

Final Solution:

The solution to the inequality is: x20x \geq 20


Would you like further clarification or details?

Here are 5 related questions for you to consider:

  1. What are the properties of cube roots when solving inequalities?
  2. How does cubing affect the direction of inequalities compared to squaring?
  3. What would change if this were a square root instead of a cube root?
  4. How do you verify solutions to inequalities like this one?
  5. Can you explain how inequalities differ from equations when graphing?

Tip: When solving inequalities, always double-check whether the operation you apply (e.g., squaring, cubing) might reverse the inequality's direction.

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Math Problem Analysis

Mathematical Concepts

Inequalities
Cube Roots
Algebra

Formulas

(x + 7)^(1/3) = Cube root formula

Theorems

Basic properties of cube roots and inequalities

Suitable Grade Level

Grades 9-10