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The equation you uploaded appears to be:

\[
4880 \times \left( 1 + \frac{r}{12} \right)^{60} = 7280
\]

This equation is likely related to compound interest, where \(r\) represents the monthly interest rate (in percentage form), and the other terms might be related to principal amounts and periods.

To solve for \(r\), let's follow these steps:

1. Divide both sides by 4880:
   \[
   \left( 1 + \frac{r}{12} \right)^{60} = \frac{7280}{4880}
   \]
   Simplifying:
   \[
   \left( 1 + \frac{r}{12} \right)^{60} = 1.4098
   \]

2. Now, take the 60th root of both sides to eliminate the exponent:
   \[
   1 + \frac{r}{12} = (1.4098)^{\frac{1}{60}}
   \]
   Approximating:
   \[
   1 + \frac{r}{12} \approx 1.005727
   \]

3. Subtract 1 from both sides:
   \[
   \frac{r}{12} = 0.005727
   \]

4. Finally, multiply both sides by 12 to solve for \(r\):
   \[
   r \approx 0.06872 \, \text{or} \, 6.872\%
   \]

Thus, the interest rate \(r\) is approximately 6.872%.

Would you like further details on any step or have any other questions?

Here are five related questions:
1. How does the equation change if the number of periods is adjusted?
2. How would this calculation differ for continuous compounding?
3. What does the monthly interest rate signify in practical terms?
4. How can you convert this monthly rate into an annual rate?
5. What if the final amount (7280) was different—how would the interest rate change?

**Tip:** In compound interest formulas, the number of compounding periods significantly affects the total amount accumulated. Always double-check this parameter!

This problem demonstrates how to solve the compound interest equation 4880 * (1 + r / 12)^60 = 7280 to find the interest rate r. It involves algebraic manipulation and exponential growth, suitable for students in Grades 11-12.

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