(2+3)-5+2^2-(5(4-2^2)-5-6)+7-10^10-(18÷9)

Let's solve the expression step by step:

### Given Expression:
\[
(2+3)-5+2^2-(5(4-2^2)-5-6)+7-10^{10}-(18\div9)
\]

### Step 1: Simplify inside the parentheses.
- \(2 + 3 = 5\)
- \(2^2 = 4\)
- \(4 - 2^2 = 4 - 4 = 0\)
- \(5 \times 0 = 0\)
- Inside the parentheses: \(5(4-2^2)-5-6\) simplifies to \(0 - 5 - 6 = -11\)

So the expression simplifies to:
\[
5 - 5 + 4 - (-11) + 7 - 10^{10} - 2
\]

### Step 2: Simplify further.
- \(5 - 5 = 0\)
- \(4 - (-11) = 4 + 11 = 15\)
- \(18 \div 9 = 2\)

The expression now is:
\[
0 + 15 + 7 - 10^{10} - 2
\]

### Step 3: Simplify addition and subtraction.
- \(15 + 7 = 22\)
- \(22 - 2 = 20\)

So the expression is:
\[
20 - 10^{10}
\]

Since \(10^{10}\) is \(10,000,000,000\):

### Final Answer:
\[
20 - 10^{10} = -9,999,999,980
\]

The simplified result is \(-9,999,999,980\).

Would you like further details or have any questions? Here are some additional questions you might explore:

1. How does exponentiation affect the order of operations in an expression?
2. What is the difference between simplifying and evaluating an expression?
3. How do parentheses change the order of operations?
4. Can you generalize the process for solving similar expressions?
5. What are common mistakes to avoid in expressions with multiple operations?

**Tip:** Always simplify expressions within parentheses first to avoid errors in complex calculations.

Learn how to solve a complex arithmetic expression step by step with detailed explanations. This problem covers order of operations, exponentiation, and arithmetic with parentheses. Suitable for Grades 7-9 students.

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