To solve the problem, we need to determine how many boys and girls are among the 50 BSCS students at PASS College.

Problem Breakdown:

1. The total number of students is 50.
2. There are 36 more girls than boys.

Let’s solve it step by step:

Let the number of boys be $x$.
Then the number of girls will be $x + 36$ (since there are 36 more girls than boys).

The total number of students is: $x + (x + 36) = 50$

Simplify and solve for $x$:

$2x + 36 = 50$ $2x = 50 - 36$ $2x = 14$ $x = 7$

Thus, the number of boys is $x = 7$, and the number of girls is: $x + 36 = 7 + 36 = 43$

Final Answer:

• Number of boys: 7
• Number of girls: 43

Would you like a detailed explanation or have further questions?

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Related Questions:

1. How do you verify that the solution satisfies the total number of students?
2. Can you generalize this approach for different numbers of students or differences in gender counts?
3. What if there were twice as many girls as boys? How would you solve it?
4. How can algebraic methods simplify similar word problems?
5. What if there were 60 students with the same conditions? What changes?

Tip:

When solving word problems, always start by defining variables for unknowns and translating relationships into equations.