Math Problem Statement

6 If the average of P numbers is Q2 and the average of Q numbers is P2 , then the average of (P + Q) numbers will be: Ans 1. P – Q 2. PQ 3. P + Q 4. 2PQ

Solution

Given:

  • The average of PP numbers is Q2Q^2.
  • The average of QQ numbers is P2P^2.

We previously found that the average of P+QP + Q numbers is: P×Q2+Q×P2P+Q\frac{P \times Q^2 + Q \times P^2}{P + Q}

We need to match this result with one of the provided options. Let's examine each option to see if it matches our result.

  1. PQP - Q
  2. PQPQ
  3. P+QP + Q
  4. 2PQ2PQ

Let's simplify our expression and check each option:

P×Q2+Q×P2P+Q\frac{P \times Q^2 + Q \times P^2}{P + Q}

Factor out a common term from the numerator:

PQ(P+Q)P+Q\frac{PQ(P + Q)}{P + Q}

Since P+QP + Q is not zero, we can cancel P+QP + Q in the numerator and denominator:

PQ(P+Q)P+Q=PQ\frac{PQ(P + Q)}{P + Q} = PQ

So, the average of P+QP + Q numbers is PQPQ.

Thus, the correct answer is:

2. PQPQ

Would you like further details or have any questions?

Here are 5 questions you might want to ask:

  1. How do you factor common terms in algebraic expressions?
  2. What are the properties of arithmetic operations in averages?
  3. Can you provide more examples of simplifying complex expressions?
  4. How do you verify solutions to multiple-choice math problems?
  5. What are some tips for solving algebra problems involving averages?

Tip: Always check your final expression against all given options in multiple-choice questions to ensure you have the correct solution.

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Math Problem Analysis

Mathematical Concepts

Averages
Arithmetic Mean
Algebra

Formulas

Average formula
Simplification of algebraic expressions

Theorems

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Suitable Grade Level

Grades 7-9