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Let’s define the variables and form an equation based on the information provided:

- Let \( t \) represent Tony's age.
- Jack is 5 years older than Tony, so Jack's age is \( t + 5 \).
- Moe is 6 years older than Tony, so Moe's age is \( t + 6 \).

The sum of the three brothers' ages is 35. So, the equation becomes:

\[
t + (t + 5) + (t + 6) = 35
\]

Let's solve this equation:

\[
t + t + 5 + t + 6 = 35
\]
\[
3t + 11 = 35
\]
\[
3t = 35 - 11
\]
\[
3t = 24
\]
\[
t = \frac{24}{3}
\]
\[
t = 8
\]

Therefore, Tony is 8 years old.

Would you like further details or have any other questions?

Here are some related questions you could consider:
1. How old is Jack based on Tony's age?
2. What is Moe’s age?
3. What would the total age be if Tony were 2 years older?
4. How would the equation change if Moe was 2 years younger than Jack instead of older than Tony?
5. Can you express the age difference between Moe and Jack in terms of Tony's age?

**Tip:** Always double-check your work by plugging values back into the equation to ensure they satisfy the original conditions.

Jack is 5 years older than Tony. Moe is 6 years older than Tony. In total the three brothers have a combined age of 35. Form and solve an equation to find the age of Tony.

Learn how to solve a basic algebra problem involving the ages of three brothers. Jack is 5 years older than Tony, Moe is 6 years older than Tony, and the sum of their ages is 35. Solve the equation step-by-step to find Tony's age.

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