Maria is twice as old as her brother. In 6 years, Maria will be 4 years older than twice her brother’s age. How old are they now?

Let Maria's current age be \( M \) and her brother's current age be \( B \).

### Step 1: Set up the equations
From the problem, we have two key pieces of information:

1. **Maria is twice as old as her brother**:
   \[
   M = 2B
   \]

2. **In 6 years, Maria will be 4 years older than twice her brother's age**:
   \[
   M + 6 = 2(B + 6) + 4
   \]

### Step 2: Solve the system of equations

#### Substitute \( M = 2B \) into the second equation:
\[
2B + 6 = 2(B + 6) + 4
\]

Simplify the right-hand side:
\[
2B + 6 = 2B + 12 + 4
\]
\[
2B + 6 = 2B + 16
\]

#### Eliminate \( 2B \) from both sides:
\[
6 = 16
\]

Clearly, this is a contradiction, meaning there's an error in the formulation. Let me adjust the reasoning.

Find out how to solve the age problem where Maria is twice as old as her brother and in 6 years, she'll be 4 years older than twice his age. This problem involves algebraic concepts such as setting up and solving a system of linear equations. Suitable for students in Grades 6-8.

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