Math Problem Statement

128 ÷ 4 + 8 ÷ (4 - 5 × 3) + 140 + 2

Solution

The expression from the image is:

128÷4+8÷(45×3)+140+2128 \div 4 + 8 \div (4 - 5 \times 3) + 140 + 2

Step-by-Step Solution:

  1. Division and Multiplication First (Order of Operations - PEMDAS):

    • 128÷4=32128 \div 4 = 32
    • 5×3=155 \times 3 = 15

    Now the expression becomes: 32+8÷(415)+140+232 + 8 \div (4 - 15) + 140 + 2

  2. Simplify Inside the Parentheses:

    • 415=114 - 15 = -11

    Now the expression is: 32+8÷(11)+140+232 + 8 \div (-11) + 140 + 2

  3. Perform the Division:

    • 8÷(11)=8110.7278 \div (-11) = -\frac{8}{11} \approx -0.727

    Now the expression becomes: 320.727+140+232 - 0.727 + 140 + 2

  4. Add the Remaining Terms:

    • 320.727+140+2=173.27332 - 0.727 + 140 + 2 = 173.273

Final Answer:

173.273173.273

Would you like any further details or clarifications?


Here are 5 related questions for practice:

  1. What is the result of 250÷5+15×2250 \div 5 + 15 \times 2?
  2. Solve 1008÷2+6×4100 - 8 \div 2 + 6 \times 4.
  3. How would you simplify 50÷10+32750 \div 10 + 3^2 - 7?
  4. If you change the subtraction to addition in 45×34 - 5 \times 3, how does the result change?
  5. What are the steps to solving 180÷(5+7)×3180 \div (5 + 7) \times 3?

Tip: Always follow the order of operations (PEMDAS: Parentheses, Exponents, Multiplication and Division, Addition and Subtraction) to avoid errors.

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Math Problem Analysis

Mathematical Concepts

Order of Operations
Division
Multiplication
Addition
Subtraction

Formulas

Order of Operations (PEMDAS)
Division and Multiplication

Theorems

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Suitable Grade Level

Grades 7-9