Solve this sum. Get to the number 112 using only the numbers 1 through 6 and you can only use four numbers. You also cannot repeat a number you have already used. You can also ONLY use multiplication, no addition, subtraction or division. The amount of numbers used to achieve 112 also has to be four numbers exactly, not less or more than four.

To solve this puzzle, we need to reach 112 using exactly four numbers from 1 to 6, and we are limited to multiplication without repeating any number.

Let's explore combinations of four numbers:

### Step-by-step exploration:
We aim for \( a \times b \times c \times d = 112 \), where \( a, b, c, d \in \{1, 2, 3, 4, 5, 6\} \) and no repetition of numbers.

- First, factorize 112:  
  \[ 112 = 2^4 \times 7 \]
  Since we cannot use the number 7, we need to find a combination of four numbers that multiplies to 112.

Let's try a combination:
- \( 4 \times 4 = 16 \)
- \( 16 \times 2 = 32 \)
- \( 32 \times 3.5 = 112 \), but 3.5 is not allowed.

Now try:
- \( 4 \times5 equal which etc.43 doesnt

Discover how to solve a puzzle where you reach 112 using exactly four numbers from 1 to 6 with multiplication only. This problem involves factorization and multiplication, and is suitable for students in Grades 5-8.

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