The expression \( 100 \div 4(2+3) \) can be simplified step by step by following the order of operations (PEMDAS/BODMAS):

1. **Parentheses first**: \( (2 + 3) = 5 \).
   \[
   100 \div 4(5)
   \]

2. **Division and multiplication** (from left to right):
   \[
   100 \div 4 = 25
   \]
   Now, multiply:
   \[
   25 \times 5 = 125
   \]

So, \( 100 \div 4(2 + 3) = 125 \).

Would you like a more detailed explanation or have any questions?

Here are 5 related questions you might find interesting:
1. How would you solve \( 200 \div 5(3 + 2) \)?
2. What happens if the division comes after the multiplication in an expression like this?
3. How do you solve \( 100 \div [4(2+3)] \) with the brackets?
4. What is the impact of changing parentheses to exponents in similar problems?
5. How do you interpret an expression if multiplication is implied, like \( 6(2+1) \)?

**Tip:** When division and multiplication are next to each other, always solve them from left to right.

Learn how to solve the expression 100 ÷ 4(2+3) by applying the order of operations (PEMDAS/BODMAS). This step-by-step solution simplifies the problem by first solving the parentheses and then performing division and multiplication in the correct order. Suitable for students in Grades 6-8.

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